Webb30 jan. 2024 · The syntax for the INTNX function is as follows: sas_date_value = intnx ('Interval', start_date, number of intervals to add); The available intervals are Day, Week, Month, Qtr (quarter) or Year and must be enclosed in quotes. The start date must be a SAS date and the number of intervals must be an integer value. Webb30 okt. 2024 · In summary, the INTNX function is a powerful tool for working with dates. It enables you to find dates that are related to a specified date. You can use the first …
How to Use the INTNX Function in SAS [Examples]
WebbSAS creates a 50-day interval in which January 1, 1960, is day 1. SAS then moves forward to day 5. (Note that the difference, or amount of movement, is four days.) SAS begins counting shifted intervals from that point. The INTNX function demonstrates that the next interval begins on January 5, 1960: Webb19 juli 2024 · In the SAS programming language, the first day of the week is Sunday, Monday is the second day, and so on. With the “weekday1w” you specify that day 1 of the week is a weekend. Using this syntax, you can create your definition of a business week. sund clo
How to Use the INTNX Function in SAS [Examples]
Webb6 mars 2024 · 2. Proc Sql; Create table dates As Select a.custid, a.Displayed_date As Start_Dt, intnx ('day',a.Displayed_date,28) As Max_dt From inscope_records a; Quit; Just learning how to use SAS EG so have created a proc SQL to add 28 days to a date. It works but it is giving me it in number format ie the days since 01/01/1960 I think it is, how do I … WebbThe following example shows how to determine the date of the start of the week that is six weeks from the week of October 17, 2003. x=intnx ('week', '17oct03'd, 6); put x date9.; INTNX returns the value 23NOV2003. For more information about working with date and time intervals, see Date and Time Intervals. Webb12 apr. 2024 · Use INTNX () instead. For generating a list of dates, a data step is more efficient. data month_ends; do i=1 to 48; *48 months = 4 years; date_end = intnx ('month', today (), -1*i, 'e'); format date_end yymmdd10.; output; end; run; Share Improve this answer Follow answered Apr 12, 2024 at 17:59 Reeza 20k 4 21 37 Add a comment Your Answer sund channel on dish